The Pythagorean Theorem Essay Example | Topics and Well Written Essays - 3500 words

The Pythagorean Theorem - Essay ExampleThe world of such a rectangle is a times b ab. Therefore the four trigons together are equal to dickens such rectangles. Their area is 2ab. As for the real whose side is c, its area is simply c. Therefore, the area of the entire square is c + 2ab . . . . . .(1)At the same time, an equal square with side a + b (Fig. 2) is made up of a square whose side is a, a square whose side is b, and two rectangles whose sides are a, b. Therefore the area of that square is a + b + 2abBut this is equal to the square formed by the triangles, line(1)a + b + 2ab = c + 2ab.Therefore, on subtracting the two rectangles -- 2ab -- from each square, we are left with a + b = c.This is the Pythagorean TheoremProof using similar triangles The Pythagorean theorem, is based on the proportionality of the sides of two similar triangles.Let ABC represent a right triangle, with the right angle located at C, as shown on the figure. We draw the altitude from superlative C , and call H its intersection with the side AB. The new triangle ACH is similar to our triangle ABC, because they both have a right angle (by definition of the altitude), and they component part the angle at A, meaning that the third angle will be the same in both triangles as well. By a similar reasoning, the triangle CBH is also similar to ABC. The similarities lead to the two ratios.. AssoThese can be written asSumming these two equalities, we obtainIn other words, the Pythagorean theoremThe Arabian mathematician Thabit ibn KurrahA clever proof by dissection which reassembles two small squares into one larger one was given by the Arabian mathematician Thabit ibn Kurrah (Ogilvy 1994, Frederickson 1997).Proof by PerigalAnother proof by dissection is due to Perigal (left...Therefore the four triangles together are equal to two such rectangles. Their area is 2ab.At the same time, an equal square with side a + b (Fig. 2) is made up of a square whose side is a, a square whose side is b, and two rectangles whose sides are a, b. Therefore the area of that square isLet ABC represent a right triangle, with the right angle located at C, as shown on the figure. We draw the altitude from intimate C, and call H its intersection with the side AB. The new triangle ACH is similar to our triangle ABC, because they both have a right angle (by definition of the altitude), and they helping the angle at A, meaning that the third angle will be the same in both triangles as well. By a similar reasoning, the triangle CBH is also similar to ABC. The similarities lead to the two ratios.. AsAnother proof by dissection is due to Perigal (left figure Pergial 1873 Dudeney 1970 Madachy 1979 Steinhaus 1999, pp. 4-5 Ball and Coxeter 1987). A related proof is effectuate using the above figure at right, in which the area of the large square is four times the area of one of the triangles plus the area of the intragroup square. From the figure d=b-a, soPerhaps the most famous proof of all times is Euclids geometric proof , although it is neither the simplest nor the most obvious.